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Percentage Yield Calculator

How much of the possible product you actually isolated from a laboratory preparation.

Yields

Units are normalised automatically — mg, g and kg can be mixed.

Mass of dry product weighed.

Maximum possible mass from the limiting reactant.

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Need the theoretical yield? Calculate it from the reaction

Laboratory calculation card

Enter the actual and theoretical yields to see the percentage yield.

Worked example: Percentage yield of aspirin from salicylic acid

A student acetylates 3.00 g of salicylic acid with 5.0 mL of acetic anhydride (density 1.08 g/mL). After recrystallisation and drying to constant weight, 2.87 g of aspirin is weighed. Find the theoretical yield and the percentage yield.

Salicylic acid (C₇H₆O₃)
3.00 g, 138.12 g/mol
Acetic anhydride
5.0 mL × 1.08 g/mL, 102.09 g/mol
Aspirin (C₉H₈O₄)
180.16 g/mol
Actual yield (dry)
2.87 g
  1. Moles of each reactant

    Salicylic acid: 3.00 g ÷ 138.12 g/mol = 0.02172 mol Acetic anhydride: (5.0 × 1.08) g ÷ 102.09 g/mol = 0.05289 mol

  2. Limiting reactant (1 : 1 equation)

    0.02172 mol < 0.05289 mol, so salicylic acid is limiting

  3. Theoretical yield

    0.02172 mol × 180.16 g/mol = 3.913 g aspirin

  4. Percentage yield

    (Actual ÷ Theoretical) × 100 = (2.87 g ÷ 3.913 g) × 100 = 0.733453 × 100 = 73.35 %

  5. Product not recovered

    3.913 g − 2.87 g = 1.043 g (26.65 %)

Theoretical yield = 3.913 g; percentage yield = 73.35 %.

About three-quarters of the aspirin the salicylic acid could form was isolated as dry solid; the rest was lost to incomplete reaction, to the mother liquor during recrystallisation and to transfers. A yield in this range is typical of a single-recrystallisation student preparation. The number says nothing about purity: a damp or contaminated product can give a higher yield, so record a melting point or a TLC alongside it.

Common mistakes

Basing the theoretical yield on the reagent in excess. Here acetic anhydride would 'predict' 9.53 g of aspirin; only the limiting reactant's moles (with the equation's mole ratio) set the maximum.
Comparing masses of different substances. Dividing 2.87 g of aspirin by 3.00 g of salicylic acid gives 95.7 %, which is not a yield; the theoretical yield must be a mass of the product.
Weighing the product before it is dry. Retained water or solvent inflates the actual yield, and is the usual reason for a yield over 100 %.
Ignoring the mole ratio when it is not 1 : 1. If two moles of reactant give one mole of product, halve the moles before multiplying by the product's molar mass.
Using the anhydrous molar mass for a hydrate (or the reverse). The theoretical yield must use the molar mass of the form that is actually weighed.
Mixing mg and g. 412 mg against 0.520 g is 79.23 %, not 792 %; this page converts both to grams first, but a hand calculation must too.

Assumptions and limitations

Assumes the theoretical yield is correct: a balanced equation, the right limiting reactant and the right molar mass of the isolated form.
Assumes the actual yield is a mass of pure, dry product. Percentage yield measures quantity, not quality.
The interpretation bands are general teaching guidance; what counts as a good yield depends on the reaction, the scale and the number of purification steps.

References

  1. Furniss BS, Hannaford AJ, Smith PWG, Tatchell AR. Vogel's Textbook of Practical Organic Chemistry. 5th ed. Harlow: Longman Scientific & Technical; 1989.
  2. International Union of Pure and Applied Chemistry. Compendium of Chemical Terminology (the 'Gold Book'). Source

Common questions

Prepared by the PharmaWallah student team. Verify results with your textbook or instructor. Report an error · Editorial policy