Pharmaceutical Analysis
Percentage Recovery Calculator
How much of the starting material you got back after an extraction, purification, assay or analytical procedure.
Experiment
Printed on the lab result card.
Amounts
Mass with mass, volume with volume. % and IU compare only with themselves.
Amount before the procedure.
Amount found after the procedure.
Try a worked example
Laboratory calculation card
Enter the initial amount and the amount recovered.
% Recovery = (Amount recovered / Initial amount) × 100
Amount = Concentration × Volume
% Loss = 100 − % Recovery
Both amounts must be in the same unit before dividing. Masses are converted through grams and volumes through millilitres, so 850 mg recovered from 1 g is 0.85 g / 1 g × 100 = 85%. In concentration mode, a mass-per-volume concentration is converted to mg/mL and a molar one to mmol/mL; multiplying by the volume in mL then gives each amount in mg or mmol.
Worked example: recovery after a liquid–liquid extraction
Illustrative values. A student shakes 50 mL of an aqueous drug solution (250 µg/mL) with an organic solvent, evaporates the organic layer and redissolves the residue in 25 mL of solvent. The redissolved extract assays at 0.462 mg/mL. How much of the drug was recovered? Enter it in Concentration × volume mode.
- Initial concentration (C₁)
- 250 µg/mL
- Initial volume (V₁)
- 50 mL
- Recovered concentration (C₂)
- 0.462 mg/mL
- Final volume (V₂)
- 25 mL
Put both concentrations in the same unit
C₁ = 250 µg/mL × 0.001 = 0.25 mg/mL (C₂ is already in mg/mL)
Initial amount = C₁ × V₁
0.25 mg/mL × 50 mL = 12.5 mg
Amount recovered = C₂ × V₂
0.462 mg/mL × 25 mL = 11.55 mg
% Recovery = (recovered / initial) × 100
(11.55 mg / 12.5 mg) × 100 = 0.924 × 100 = 92.40 %
% Loss = 100 − % recovery
100 − 92.40 = 7.60 %
% Recovery = 92.40 % (7.60 % of the drug was not recovered)
Notice that the concentration went up (0.25 → 0.462 mg/mL) while the recovery is below 100 %: the extract was made up to half the original volume. Recovery compares amounts, never concentrations. Whether 92.40 % is acceptable depends on the procedure — the criteria come from your practical manual or validated method, not from this number alone.
Common mistakes
Assumptions and limitations
Keep learning
References
- International Council for Harmonisation. ICH Q2(R2): Validation of Analytical Procedures. Step 4, adopted 1 November 2023. Source
- United States Pharmacopeia–National Formulary. General Chapter <1225> Validation of Compendial Procedures. Rockville (MD): USP.
- Stockton SJ. Stoklosa and Ansel's Pharmaceutical Calculations. 16th ed. Philadelphia: Wolters Kluwer; 2021.
Common questions
On paper it often is. A product that is not fully dry still holds solvent or water; an extract can carry co-extracted impurities that add weight or absorbance; a pipetting or dilution error, or a drifting calibration curve, inflates a measured concentration. A result above 100% is a signal to re-check the data, not proof that something was created.
Recovery compares the amount of the same substance before and after a step — you started with 2.00 g of crude aspirin and got 1.64 g back. Percentage yield compares the product you isolated with the theoretical amount a reaction could form from its limiting reactant.
A known amount of the analyte is added (spiked) to a blank or sample matrix and then measured with the method. The found amount as a percentage of the added amount shows how accurate the method is in that matrix. Acceptance limits come from the validation protocol or the applicable guideline.
A mass and a volume are different quantities; converting between them needs the density of that specific material. Convert one of them first (mass = volume × density), then enter both as masses.
Yes, as long as both values use it — for example a labelled 100% content and a found 98.7%, or 10,000 IU added and 9,640 IU found. IU cannot be converted to a mass without substance-specific information, so it is never mixed with other units.
Prepared by the PharmaWallah student team. Verify results with your textbook or instructor. Report an error · Editorial policy