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Pharmacokinetics

Clearance Calculator

Works out drug clearance (CL) from a single dose and its AUC, or from an infusion rate and the steady-state level.

Clearance (CL)

Enter the dose and the AUC to see the clearance.

Inputs

mg

The IV dose given.

mg·h/L

Area under the concentration–time curve, 0 to infinity.

L

Enter it to also get the half-life: t½ = 0.693 × Vd / CL.

Try an example drug

Clearance scale

Total clearance bands used for the interpretation.

< 0.5 L/hSevere impairment
0.5 – 2 L/hReduced
2 – 10 L/hNormal
10 – 30 L/hHigh
≥ 30 L/hFlow-limited

Worked example: Clearance and half-life from a single IV dose

A volunteer in a teaching study receives 400 mg of Drug X as an IV bolus. The area under the plasma concentration–time curve, extrapolated to infinity, is 64 mg·h/L, and the volume of distribution is 45 L. Find the total clearance and the half-life.

Dose (IV)
400 mg
AUC₀–∞
64 mg·h/L
Vd (optional field)
45 L
Method
Single dose
  1. Clearance

    CL = Dose ÷ AUC = 400 mg ÷ 64 mg·h/L = 6.250 L/h

  2. Check the units

    mg ÷ (mg·h/L) = L/h

  3. Per kilogram (70 kg reference)

    6.25 L/h ÷ 70 kg = 0.0893 L/h/kg

  4. Half-life

    t½ = 0.693 × Vd ÷ CL = 0.693 × 45 L ÷ 6.25 L/h = 4.99 h

CL = 6.250 L/h (≈ 104 mL/min); t½ ≈ 4.99 h.

Every hour the body clears the drug from about 6.25 L of plasma. Because Vd is 45 L, that is roughly 14 % of the volume per hour (kₑ = CL ÷ Vd ≈ 0.139 h⁻¹), which is why the half-life is about 5 hours. This is an educational calculation on illustrative values; whether a clearance is 'normal' depends on the drug, so it does not by itself describe a patient's organ function.

Common mistakes

Using an oral dose and AUC and calling the answer total clearance. Dose ÷ AUC after an oral dose is CL/F; divide by F (or multiply the dose by F first) to get true clearance.
Using a truncated AUC (0 to the last sample) instead of AUC₀–∞. A smaller AUC overestimates clearance.
Mixing units: AUC in µg·h/mL is numerically the same as mg·h/L, but AUC in µg·h/L with a dose in mg gives a clearance 1000 times too small.
Converting L/h to mL/min wrongly. Multiply by 1000 and divide by 60 (6.25 L/h = 104 mL/min), not the other way round.
Drawing the 'steady-state' level before about 4–5 half-lives of constant infusion. The level is still rising, so R₀ ÷ Css overestimates clearance.
Dividing by 70 kg for every patient. The per-kg figure here is for a 70 kg reference adult; use the patient's actual weight in practice.

Assumptions and limitations

Assumes linear (first-order) pharmacokinetics: clearance is the same at every concentration. Saturable elimination breaks this.
Dose ÷ AUC gives total systemic clearance only for an intravenous dose that is completely available.
R₀ ÷ Css assumes a true steady state and a constant infusion rate; a loading dose or a changing rate invalidates it.
The interpretation bands and the organ chart are general teaching aids, not drug-specific ranges.

References

  1. Ducharme MP, Shargel L, editors. Shargel and Yu's Applied Biopharmaceutics & Pharmacokinetics. 8th ed. New York: McGraw Hill; 2022.
  2. Rowland and Tozer's Clinical Pharmacokinetics and Pharmacodynamics: Concepts and Applications. 5th ed. Philadelphia: Wolters Kluwer; 2019.

Common questions

Prepared by the PharmaWallah student team. Verify results with your textbook or instructor. Report an error · Editorial policy