Pharmacokinetics
Volume of Distribution Calculator
Works out the apparent volume of distribution (Vd) from an IV dose and the plasma concentration it produced.
Volume of distribution
Enter the IV dose and the plasma concentration at time zero (C₀).
Inputs
The total dose given as an intravenous bolus.
Concentration at time zero after the IV bolus (back-extrapolated).
Used only for Vd per kg. Left blank, 70 kg is assumed.
Try an example drug
Interpreting Vd
Bands from the MSD Manual, in litres per kilogram.
Vd = Dose / C₀
Vd (L/kg) = Vd / body weight
Dose is the IV bolus in mg; C₀ is the plasma concentration at time zero in mg/L, usually found by back-extrapolating the log-concentration line to t = 0. Dividing the amount by the concentration gives litres.
Expressing Vd per kg lets you compare it with real body spaces: plasma is about 0.04 L/kg, extracellular fluid about 0.2 L/kg and total body water about 0.6 L/kg. Anything much larger means the drug is held in tissues. Interpretation per the MSD Manual.
Worked example: Vd from an IV bolus, with C₀ found by back-extrapolation
A 64 kg volunteer in a teaching study receives 500 mg of Drug X as an IV bolus. Plasma levels are 10.0 mg/L at 2 h and 6.4 mg/L at 6 h, both on the log-linear elimination phase. Find C₀, then the volume of distribution in L and L/kg.
- Dose (IV bolus)
- 500 mg
- C at 2 h
- 10.0 mg/L
- C at 6 h
- 6.4 mg/L
- Body weight
- 64 kg
Elimination rate constant
kₑ = ln(C₁ ÷ C₂) ÷ (t₂ − t₁) = ln(10.0 ÷ 6.4) ÷ 4 h = 0.1116 h⁻¹
Back-extrapolate to t = 0
C₀ = C₁ × e^(kₑ·t₁) = C₁ × (C₁ ÷ C₂)^(t₁ ÷ (t₂ − t₁)) = 10.0 × 1.5625^0.5 = 12.5 mg/L
Volume of distribution
Vd = Dose ÷ C₀ = 500 mg ÷ 12.5 mg/L = 40.00 L
Per kilogram
Vd = 40.00 L ÷ 64 kg = 0.625 L/kg
Vd = 40.00 L (0.625 L/kg) — the calculator's 'Total Body Water' band.
To give 12.5 mg/L, the 500 mg behaves as if it were dissolved in 40 L — close to total body water for a 64 kg adult (about 0.6 L/kg). It also gives the loading dose for a target level: 40 L × 15 mg/L = 600 mg. It does not say where the drug actually is: Vd is an apparent volume, and a value like this is equally consistent with a drug spread through body water or one partly bound in tissue and partly in plasma. Illustrative values for an educational calculation.
Common mistakes
Assumptions and limitations
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References
- Ducharme MP, Shargel L, editors. Shargel and Yu's Applied Biopharmaceutics & Pharmacokinetics. 8th ed. New York: McGraw Hill; 2022.
- Rowland and Tozer's Clinical Pharmacokinetics and Pharmacodynamics: Concepts and Applications. 5th ed. Philadelphia: Wolters Kluwer; 2019.
Common questions
Because it is an apparent volume. If a drug binds strongly in tissue, very little stays in plasma, so the measured concentration is low and Dose ÷ C₀ becomes huge. Chloroquine and digoxin are classic examples.
Dose in mg and concentration in mg/L, giving Vd in litres. If your level is reported in µg/L or ng/mL, convert it to mg/L first (1 ng/mL = 0.001 mg/L), otherwise the answer is out by a factor of a thousand.
The plasma concentration at the instant of the IV bolus, before any elimination. You cannot sample at exactly t = 0, so plot log concentration against time and extrapolate the straight elimination line back to the y-axis.
Mainly for loading doses: loading dose = Vd × target concentration. A large Vd also warns that a drug will be slow to leave the body and poorly removed by dialysis.
Prepared by the PharmaWallah student team. Verify results with your textbook or instructor. Report an error · Editorial policy